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11u^2-35u+12=0
a = 11; b = -35; c = +12;
Δ = b2-4ac
Δ = -352-4·11·12
Δ = 697
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{697}}{2*11}=\frac{35-\sqrt{697}}{22} $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{697}}{2*11}=\frac{35+\sqrt{697}}{22} $
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